jQuery使用一个按钮控制图片的伸缩实现思路

  技术百科     |      2026-01-17 18:34
复制代码 代码如下:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<style type="text/css">
#img1
{
width: 500px;
height: 400px;
border: solid 1px #ccc;
display:none;
}
</style>
<script src="jquery-1.9.1.js" type="text/javascript"></script>
<script type="text/javascript">
var count = 0;
$(function () {
$('#Button1').click(function () {
if (count % 2 != 0) {
$('#img1').hide(5000);
}
else {
$('#img1').show(5000);
}
count++;
})
})
</script>
</head>
<body>
<form id="form1" runat="server">
<div>
<img id="img1" src="images/1.jpg" />
<input id="Button1" type="button" value="点我看看" />
</div>
</form>
</body>
</html>